article · Real Analysis Exchange · 1998
A SIMPLE PROOF THAT (s)/(s⁰) IS A COMPLETE BOOLEAN ALGEBRA
Cited by 1Abstract and details only
Abstract
Let $X$ be a complete separable metric space, let $(s)$ be the set of all Marczewski \cite{sm} measurable subsets of $X$, and let $(s^0)$ be the the set of all Marczewski null subsets of $X$. It is already known that $(s)/(s^0)$ is a complete Boolean algebra, but the known proofs of this involve complicated preliminaries. We present a simple proof that $(s)/(s^0)$ is a complete Boolean algebra.
Cite this paper
Baldwin, & Brown. (1998). A SIMPLE PROOF THAT (s)/(s⁰) IS A COMPLETE BOOLEAN ALGEBRA. Real Analysis Exchange, 24(2), 855. https://doi.org/10.2307/44153005
Baldwin, , and Brown. “A SIMPLE PROOF THAT (s)/(s⁰) IS A COMPLETE BOOLEAN ALGEBRA.” Real Analysis Exchange, vol. 24, no. 2, 1998, p. 855, https://doi.org/10.2307/44153005.
Baldwin, and Brown. 1998. “A SIMPLE PROOF THAT (s)/(s⁰) IS A COMPLETE BOOLEAN ALGEBRA.” Real Analysis Exchange 24 (2): 855. https://doi.org/10.2307/44153005.
Baldwin and Brown (1998) ‘A SIMPLE PROOF THAT (s)/(s⁰) IS A COMPLETE BOOLEAN ALGEBRA’, Real Analysis Exchange, 24(2), p. 855. Available at: https://doi.org/10.2307/44153005.
@article{baldwin1998simple,
title = {{A SIMPLE PROOF THAT (s)/(s⁰) IS A COMPLETE BOOLEAN ALGEBRA}},
author = {Baldwin and Brown},
journal = {Real Analysis Exchange},
volume = {24},
number = {2},
pages = {855},
year = {1998},
doi = {10.2307/44153005}
}Made from the index record. Check names, capitalisation and page numbers against the paper. Need another style? AI for Research has over 10,000.