article · Extracta Mathematicae · 2004
On Continuous Surjections from Cantor Set
Cited by 2Open access
Abstract
It is a famous result of Alexandroff and Urysohn [1] that every compact metric space is a continuous image of Cantor set ∆. In this short note we complement this result by showing that a certain “uniqueness ” property holds. Given topological spaces X and Y, let C(X,Y) denote the collection of all continuous mappings from X to Y. If Y is metrized by d, one can endow C(X,Y) with the uniform metric dist(f, g) = sup x∈X d(f(x), g(x)). It is clear that if ϕ is a homeomorphism of X, the map f 7 → ϕ ◦ f is an isometry of C(X,Y). Our result is the following. Theorem. Let K be a compact metric space and let f and g be two continuous mappings from ∆ onto K. For every ε> 0 there exists a homeo-morphism ϕ of ∆ such that dist(g, f ◦ ϕ) < ε. Before going into the proof, let us fix some notations. We regard the points of ∆ = {0, 1}N as functions x: N → {0, 1} and we write ∆(n) for the set of all two-valued functions y: {1, 2,..., n} → {0, 1}. Given y ∈ ∆(n), put ∆y = {x ∈ ∆ : x(k) = y(k), 1 ≤ k ≤ n}. Obviously ∆y is homeomorphic to ∆. The n-th standard decomposition of ∆ is the partition of ∆ into the 2n clopen sets
Cite this paper
Sánchez, F. C. (2004). On Continuous Surjections from Cantor Set. Extracta Mathematicae, 19(3), 335–338.
Sánchez, Félix Cabello. “On Continuous Surjections from Cantor Set.” Extracta Mathematicae, vol. 19, no. 3, 2004, pp. 335–38.
Sánchez, Félix Cabello. 2004. “On Continuous Surjections from Cantor Set.” Extracta Mathematicae 19 (3): 335–38.
Sánchez, F.C. (2004) ‘On Continuous Surjections from Cantor Set’, Extracta Mathematicae, 19(3), pp. 335–338.
@article{sanchez2004continuous,
title = {{On Continuous Surjections from Cantor Set}},
author = {Sánchez, Félix Cabello},
journal = {Extracta Mathematicae},
volume = {19},
number = {3},
pages = {335--338},
year = {2004}
}Made from the index record. Check names, capitalisation and page numbers against the paper. Need another style? AI for Research has over 10,000.
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